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Two hollow conducting spheres of radius  \mathrm{R}_{1}$ and $\mathrm{R}_{2}$ $\left(\mathrm{R}_{1}>> \mathrm{R}_{2}\right) have equal charges. The potential would be:
 

Option: 1

more on smaller sphere
 


Option: 2

equal on both the spheres
 


Option: 3

dependent on the material property of the sphere
 


Option: 4

more on bigger sphere


Answers (1)

best_answer

Let the potential of sphere of radius \mathrm{R}_{1} \; \text{and} \; \mathrm{R}_{2}\; \text{be} \; \mathrm{V}_{1} \& \mathrm{V}_{2} respectively
\begin{aligned} & V_{1} =\frac{K Q}{R_{1}} \\ & V_{2} =\frac{K Q}{R_{2}} \\ & \because R_{1} >R_{2} \\ &\therefore V_{1}<V_{2} \end{aligned}
The potential would be more on smaller sphere.
The correct option is (1)

Posted by

manish painkra

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