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Two identical capacitors \mathrm{A} and \mathrm{B} are charged to the same potential \mathrm{V}and are connected in two circuits at \mathrm{t = 0}, as shown in figure. The charge on the capacitors at time \mathrm{t = CR} are respectively

Option: 1

\mathrm{VC,VC}


Option: 2

\mathrm{\frac{V C}{e}, V C}


Option: 3

\mathrm{V C, \frac{V C}{e}}


Option: 4

\mathrm{\frac{V C}{e}, \frac{V C}{e}}


Answers (1)

best_answer

Time \mathrm{t=CR} CR is known as time constant. It is time in which charge on the capacitor
decreases to \mathrm{\frac{1}{e}} times of it’s initial charge (steady state charge).
In figure \mathrm{(i)PN} PN junction diode is in forward bias, so current will flow the circuit \mathrm{i. e.,}
charge on the capacitor decrease and in time \mathrm{t} it becomes \mathrm{Q=\frac{1}{e}(Q_{0})}; where
\mathrm{Q_o=C V \Rightarrow Q=\frac{C V}{e}}
In figure \mathrm{(ii)P-N} junction diode is in reverse bias, so no current will flow through the circuit hence change on capacitor will not decay and it remains same, \mathrm{i. e. ,} \mathrm{CV} after time \mathrm{t}.

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