Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Two parallel line charges  and <img alt="-\lambda" src="https://entrancecorner.oncodecogs.com/gi

Two parallel line charges +\lambda and -\lambda are placed with a separation R in free space. The net electric field exactly mid way between the two line charge is -

Option: 1

zero


Option: 2

\frac{2 \lambda}{\pi \epsilon_0 K}


Option: 3

\frac{\lambda}{\pi \epsilon_0 R}


Option: 4

\frac{\lambda}{4 \pi \epsilon \nu R}


Answers (1)

best_answer

 we know that,
\mathrm{E=\frac{2 k \lambda}{R} }
but,
\mathrm{\begin{aligned} & E_{\text {Net }}=\left|E_1\right|+\left|E_2\right| \\ &=2\left(\frac{2 k \lambda}{R}\right)=\frac{4 \lambda}{4 \pi t 0 R} \\ &=\frac{\lambda}{\pi t_0 R} \end{aligned} }

Posted by

Ajit Kumar Dubey

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NTA reopens NEET fee refund window; submit bank details by June 30
anam-khan

NEET Rank Predictor 2026: Calculate probable re-NEET AIQ rank, percentiles for MBBS, BDS admission
anam-khan

How to calculate marks using NEET answer key?

Latest Question