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  • Two particles each of mass m and charge q, are attached to the two ends of a light right rod of length <img alt="2l" src="https://entrancecorner.oncodecogs.com/gif.late

Two particles each of mass m and charge q, are attached to the two ends of a light right rod of length 2l. The rod is rotated at a constant angular speed about a perpendicular axis passing through its centre. The ratio of the magnitudes of the magnetic moment of the system and its angular momentum about the centre of the rod is

Option: 1

\frac{q}{2 m}


Option: 2

\frac{q}{m}


Option: 3

\frac{2q}{m}


Option: 4

\frac{q}{\pi m}


Answers (1)

best_answer

Using ampere's law

\mu_m=I A

\because charge q moving in a circular path of radius 2l.

so \mu_m=\frac{q v}{2 \pi(2 l)} \times \pi(2 l)^2=q v l.

The angular momentum L=mv(2l)

\because \frac{\mu_m}{L}=\frac{q v l}{mv(2 l)}=\frac{q}{2 m}

Posted by

Ritika Kankaria

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