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Two resistors of resistance, 100 \Omega and 200 \Omega are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in 100 \Omega to that in 200 \Omega in a given time is:

Option: 1

2:1


Option: 2

1:4


Option: 3

4:1


Option: 4

1:2


Answers (1)

best_answer

\begin{aligned} &I_{1}=\frac{I(200)}{(300)}=\frac{2 I}{3} \\ &I_{2}=\frac{I(100)}{200+100}=\frac{I}{3} \\ &\frac{H_{1}}{H_{2}}=\frac{I_{1}^{2} R_{1} t}{I_{2}^{2} R_{2} t}=\frac{2}{1} \end{aligned}

The correct option is (1)

Posted by

Divya Prakash Singh

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