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Two small spheres each having the charge \small +Q are suspended by insulating of length \small L from a hook. This arrangment is taken in space where there is no gravitational effect, then the angle between the two suspensions and the tension in each will be -

Option: 1

180^{\circ}, \frac{1}{4 \pi \epsilon_0} \frac{Q^2}{(2 L)^2}


Option: 2

90^{\circ}, \frac{1}{4 \pi \epsilon_0} \frac{Q^2}{L^2}


Option: 3

180^{\circ}, \frac{1}{4 \pi \epsilon_0} \frac{Q^2}{2 L^2}


Option: 4

180^{\circ}, \frac{1}{4 \pi \epsilon_0} \frac{Q^2}{L^2}


Answers (1)

best_answer

\text { According to the question, }

\text { Angle must be } \pi / 2 \text { or } 180^{\circ}

F=\frac{1}{4 \pi \epsilon_0} \frac{Q^2}{(2 L)^2}

Posted by

sudhir kumar

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