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Two trains start from the same station at 11:00 p.m. in opposite directions at speeds of 72 km/h and 63 km/h, respectively. At what time will they be 810 km apart?

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Given - 

  • Speed of Train A = 72 km/h
  • Speed of Train B = 63 km/h
  • Total distance to be apart = 810 km

Solution - The relative Speed (since they are moving in opposite directions) $= 72+63=135km/h$

Time needed to be 810 km apart= $$ \frac {Distance} {speed} $$

$$ \text {Time} = \frac {810} {135} $$

As start time = 11:00 p.m., so time after 6 hours = 5:00 a.m.

Posted by

Saniya Khatri

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