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Two very long straight parallel wires carry currents I and –I respectively. The distance between the wires is d. At a certain instant of time, a point charge q is at a point equidistant from the two wires, in the plane of the wires. Its instantaneous velocity $v$ is perpendicular to this plane. The magnitude of the force due to magnetic field acting on the charge at this instant is:
Option: 1
$\mathrm{\frac{\mu_0 \text { lqu }}{2 \pi d}}$

Option: 2
$\mathrm{\frac{\mu_0 \text { lqu }}{\pi d}}$

Option: 3
$\mathrm{\frac{2 \mu_0 l q u}{\pi d}}$

Option: 4
zero

Answers (1)

best_answer

$\mathrm{\overrightarrow{V} \| \overrightarrow{B}}$

Posted by

Devendra Khairwa

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