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  • wavelength emitted by an atom of atomic number <img alt="\mathrm{Z=11}" src="https://

\mathrm{K_\alpha} wavelength emitted by an atom of atomic number \mathrm{Z=11} is \mathrm{\lambda}. Find the atomic number for an atom that emits \mathrm{K_\alpha} radiation with wavelength \mathrm{4 \lambda} :


 

Option: 1

\mathrm{Z=6}
 


Option: 2

\mathrm{Z=4}


Option: 3

\mathrm{Z=11}


Option: 4

\mathrm{Z=44}


Answers (1)

best_answer

\mathrm{\frac{1}{\lambda} \propto(Z-1)^2 }

\mathrm{ \therefore \frac{\lambda_1}{\lambda_2} =\left(\frac{Z_2-1}{Z_1-1}\right)^2 }

\mathrm{ \text { or } \frac{1}{4} =\left(\frac{Z_2-1}{11-1}\right)^2 }

Solving this, we get \mathrm{ Z_2=6 }

\therefore option 1 is correct.
 

Posted by

Ajit Kumar Dubey

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