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Wavelength of $\mathrm{K_\alpha X-}$ ray of an element $\mathrm{A}$ is $\mathrm{\lambda_1}$ and wavelength of $\mathrm{K_\alpha X}$ -ray element $\mathrm{B}$ is $\mathrm{\lambda_2\frac{\lambda_1}{\lambda_2}}$ is equal to $\frac{1}{4}$ and $\mathrm{Z_1}$ and $\mathrm{Z_2}$ are the atomic numbers of element $\mathrm{A \: and\: B}$ respectively. Then relation between $\mathrm{Z_1\: and \: \: Z_2}$ are given by :

Option: 1
$\mathrm{2 Z_2-Z_1=1}$

Option: 2
$\mathrm{Z_2-2 Z_1=1}$

Option: 3
$\mathrm{\frac{Z_2}{Z_1}=4}$

Option: 4
$\mathrm{\frac{Z_1}{Z_2}=4}$

Answers (1)

best_answer

$\mathrm{\left(\frac{\lambda_2}{\lambda_1}\right)^{1 / 2}=\frac{\left(Z_1-1\right)}{\left(Z_2-1\right)} }$

$\mathrm{(4)^{1 / 2}=\frac{\left(Z_1-1\right)}{\left(Z_2-1\right)} }$

$\mathrm{2\left(Z_2-1\right)=\left(Z_1-1\right) }$

$\mathrm{2 Z_2-Z_1=1 }$

Posted by

HARSH KANKARIA

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