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  • We wish to observe an object which is in size. The minimum energy photon that can be used -<div class='qn

We wish to observe an object which is 2.5 \AA in size. The minimum energy photon that can be used -

Option: 1

5 KeV


Option: 2

8 KeV


Option: 3

10 KeV


Option: 4

12 KeV


Answers (1)

best_answer

In order for scattering to occur, the wavelength of the waves must be of the same order of magnitude or smaller than the size of the object being observed. Hence the largest possible wavelength we can use in the present problem is \lambda _{max} = 2.5 \AA . Hence minimum energy is \mathrm{E}_{\min }=\mathrm{h} v_{\min }=\frac{\mathrm{hc}}{\lambda_{\max }}=\frac{12.40 \times 10^3}{2.5 \AA} \mathrm{eV} \cdot \AA=4.96 \times 10^3 \mathrm{eV}=5 \mathrm{KeV}

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