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What is the equation for the gravitational field due to a uniform circular ring of radius 'a' at a point on its axis?

Option: 1

 I= \frac{GMr}{\left ( a^{2}+r^{2} \right )^{\frac{3}{2}}}


Option: 2

 I= \frac{GMr}{\left ( 2a^{2}+r^{2} \right )^{\frac{3}{2}}}


Option: 3

 I= \frac{GMr}{\left ( a^{2}+r^{2} \right )^{\frac{5}{2}}}


Option: 4

 I= \frac{2GMr}{\left ( a^{2}+r^{2} \right )^{\frac{3}{2}}}


Answers (1)

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The gravitational field due to a uniform circular ring at a point on its axis is given by the equation  I= \frac{GMr}{\left ( a^{2}+r^{2} \right )^{\frac{3}{2}}}, where m is the mass of the ring, a  is the radius of the ring, and G is the gravitational constant.

 

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Kuldeep Maurya

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