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What is the magnetic field produced at the center of a hydrogen atom due to revolution of its electron in first orbit (k-orbit)?

Option: 1

12.4 T


Option: 2

14.4 T


Option: 3

10.3 T


Option: 4

11.9 T


Answers (1)

best_answer

Time period of revolution, T = \frac{2\pi A}{v}

So, the circular loop formed due to revolution of the electron carries an effective current,  \

I= \frac{Change }{time \;period}=\frac{e}{T}=\frac{ev}{2\pi A}

So, the magnetic field at the center of atom, 

B = \frac{\mu_0I}{2A}=\frac{\mu_0}{4\pi}.\frac{ev}{A^2}

=10^{-7}\times\frac{(1.6\times10^{-19})\times(2.19\times10^{6})}{(0.53\times10^{-10})^{2}}

= 12.4 T

Posted by

HARSH KANKARIA

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