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  • What is the power output of a  reactor if it treks 30 days to use up  of fuel an

What is the power output of a  reactor if it treks 30 days to use up 2 \mathrm{~kg} of fuel and if each fission gives  185 \mathrm{MeV} of usable energy -

Option: 1

6.06 \times 10^7 \mathrm{w}


Option: 2

7.05 \times 10^9 \mathrm{~W}


Option: 3

8.54 \times 10^7 \omega


Option: 4

6.06 \times 10^6 \mathrm{w}


Answers (1)

best_answer

The number of \mathrm{92^{235} in\, \, 2 \mathrm{~kg}}
\mathrm{ \begin{aligned} & N=\frac{(2 \times 1000)}{235} \times 6.02 \times 10^{23} . \\ & N=5.12 \times 10^{24} \end{aligned} }
The fission of each \mathrm{ 920^{235}} produces energy\mathrm{=185 \mathrm{MeV}}
Total energy produces
\mathrm{\begin{aligned} E & =(5.12 \times 10)^{24} \times\left(185 \times 1.6 \times 10^{-13}\right) \mathrm{J} \\ & =1572.3 \times 10^{11} \mathrm{~J} \end{aligned}}
\mathrm{The\, \, power \, \, output,\, \, p=\frac{E}{t}=\frac{1572.3 \times 10^{11}}{30 \times 24 \times 3600} }
\mathrm{=6.06 \times 10^7 \mathrm{~W} \text { Ans. } }


 

 

Posted by

Ritika Jonwal

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