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  • When a metallic surface is illuminated with monochromatic light of wavelength  , the stopping potential is

When a metallic surface is illuminated with monochromatic light of wavelength \lambda , the stopping potential is 5V_{0} . When the same surface is illuminated with light of wavelength 3\lambda , the stopping potential is V_{0} . Then the work function of the metallic surface is -

Option: 1

\frac{hc}{6\lambda }


Option: 2

\frac{hc}{5\lambda}


Option: 3

\frac{hc}{4\lambda}


Option: 4

\frac{2hc}{4\lambda}


Answers (1)

best_answer

5eV_{0}=\frac{hc}{\lambda}-W                                   ..............................\left ( 1 \right )
eV_{0}=\frac{hc}{3\lambda}-W                                     ..............................\left ( 2 \right )
Solving equation (1) & (2)
\begin{aligned} & \frac{\mathrm{hc}}{\lambda}-\mathrm{W}=\frac{5 \mathrm{hc}}{3 \lambda}-5 \mathrm{~W} \\ & 4 \mathrm{~W}=\frac{2 \mathrm{hc}}{3 \lambda} \Rightarrow \mathrm{W}=\frac{\mathrm{hc}}{6 \lambda} \end{aligned}

Posted by

Divya Prakash Singh

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