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  • Which is incorrectly given according to order indicated?Option: 1 <img alt="\mathrm{F}_{2}>\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{I}_{2};\t

Which is incorrectly given according to order indicated?

Option: 1

\mathrm{F}_{2}>\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{I}_{2};\text{Oxidising power}


Option: 2

\mathrm{HI}>\mathrm{HBr}>\mathrm{HCl}>\mathrm{HF};\text{ Acidic strength}


Option: 3

\mathrm{F}_{2}>\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{I}_{2}; \text{Bond dissociation enthalpy}


Option: 4

\mathrm{HF}>\mathrm{HI}>\mathrm{HBr}>\mathrm{HCl}; \text{Boiling point}


Answers (1)

best_answer

The correct order of bond dissociation enthalpy among halogen is \mathrm{Cl}_{2}>\mathrm{F}_{2}>\mathrm{Br}_{2}>\mathrm{I}_{2}.

Bond dissociation enthalpy of \mathrm{Cl}_{2} is greater than \mathrm{F}_{2} due to repulsion between lone pairs in \mathrm{F}_{2} which is smaller than \mathrm{Cl}_{2}.

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Rishabh

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