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Which of the following statements are correct?

a) \mathrm{Fe}^{2+} gives brown colour with ammonium thiocyanate.
b) \mathrm{Fe}^{3+} gives brown colour with potassium ferricyanide.
c) \mathrm{Fe}^{2+} gives blue precipitate with potassium ferricyanide.
d) \mathrm{Fe}^{3+} gives red colour with potassium thiocyanate.

Option: 1

a and b


Option: 2

b and c


Option: 3

c and d 


Option: 4

a and d


Answers (1)

best_answer

\mathrm{Fe^{2+}} on reaction with potassium ferricyanide will give a dark blue precipitate. This precipitate is known as Turnbull's blue and it is identical to Prussian blue.

\mathrm{K}^{+}(\mathrm{aq})+\mathrm{Fe}^{2+}(\mathrm{aq})+\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}(\mathrm{aq}) \rightleftharpoons \mathrm{KFe}\left[\mathrm{Fe}(\mathrm{CN})_6\right](\mathrm{s}) \rightarrow \text { Prussian blue }

\text{Fe}^{3+} on reaction with potassium thiocyanate (KSCN) gives a blood-red solution.

\mathrm{FeCl}_3+3 \mathrm{KSCN} \rightarrow\underset{ \textup{blood red colour}}{ \mathrm{Fe}(\mathrm{SCN})_3}+3 \mathrm{KCl}

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Divya Prakash Singh

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