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  • Which one of the followings has maximum number of atoms?Option: 1 1g of Li(s) [Atomic mass of Li = 7 ]<str

Which one of the followings has maximum number of atoms?

Option: 1

1g of Li(s) [Atomic mass of Li = 7 ]


Option: 2

1g of Ag(s) [ Atomic mass of Ag = 108 ]


Option: 3

1g of Mg(s) [ Atomic mass of Mg =  24 ]


Option: 4

1g of O2(g) [ Atomic mass of O = 16 ]


Answers (1)

best_answer

For Li:

Number of atoms in 1 g \mathrm{Li=\frac{N_{A}}{7}}

For Ag:

Number of atoms in 1 g \mathrm{Ag= \frac{N_{A}}{108}}

For Mg:

Number of atoms in 1 g  \mathrm{Mg= \frac{N_{A}}{24}}

For O2:

Number of atoms in 1 g \mathrm{O_{2}=\frac{(2\times N_A)}{32}=\frac{N_{A}}{16}}

Thus, the number of atoms in 1 g of Li is the highest among these.

Therefore, Option(1) is correct.

Posted by

Gunjita

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