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A thermodynamic system undergoes cyclic process ABCDA as shown in fig. the work done by the system in the cycle is:

• Option 1)

$P_{o}V_{o}$

• Option 2)

$2P_{o}V_{o}$

• Option 3)

$\frac{P_{o}V_{o}}{2}$

• Option 4)

$Zero$

Using Cyclic Process - A cyclic process consist of a number of changes that return the system back to its initial state.   - wherein in cyclic process    Work done in cyclic process = Area of the cycle In the upper half, cycle is anti-clockwise while in lower half it is clockwise. Hence, net work done is zero. Option 1) This option is incorrect Option 2) This option is incorrect Option...
Medical
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A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 2 V, and then adiabatically to a volume 16 V. the final pressure of the gas is:

$take\:\:\left( \gamma= \frac{5}{3} \right )$

• Option 1)

64 P

• Option 2)

32 P

• Option 3)

$\frac{P}{64}$

• Option 4)

16 P

As learnt in Equation of state -   - wherein On solving    For Isothermal expansion, For adiabatic expansion,   Option 1) 64 P This option is incorrect Option 2) 32 P This option is incorrect Option 3) This option is correct Option 4) 16 P This option is incorrect
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