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The number of sigma (\sigma) and pi(\pi) bonds in pent-2-en-4-yne is:

  • Option 1)

    10 \sigma bonds and 3 \pi bonds

  • Option 2)

    \sigma bonds and 5 \pi bonds

  • Option 3)

    11 \sigma bonds and 2 \pi bonds

  • Option 4)

    13 \sigma bonds and no \pi bonds

Option 1 Structure of pent-2-en-4-yne Here there are 10  bonds  and  bonds And 3  bonds   and Option 1)10  bonds and 3  bondsOption 2)8  bonds and 5  bondsOption 3)11  bonds and 2  bondsOption 4)13  bonds and no  bonds

An alkane "A" on reaction with O3 and Zn-H2O gives propane and ethanal in equimolar ratio. Addition of HCl to Alkane "A" gives "B" as the major product. The structure of the product "B" is

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

This oxidation of alkene occurs at the double bond. Thus, propane & ethanol must combine to give the alkene             (Propanone)                                                                                                       Now this reacts with HCl to form B as follows:                                                                         ...

The structure of intermediate A, in the following reaction, is:

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

Option 2   Cumene is oxidized in air, which removes the tertiary benzylic hydrogen from cumene and hence forms cumene radical. The cumene radical then bonds with an oxygen molecule to give cumene peroxide radical, which in turn forms cumene hydroperoxide by abstracting benzylic hydrogen from the cumene molecule.  Option 1)Option 2)Option 3)Option 4)

The most suitable reagent for the following conversion is:

H_{3}C -C\equiv C-CH_{3}\xrightarrow[quinoline]{H_{2},Pd/C,}

  • Option 1)

    Na/liquid NH3

  • Option 2)

    H2, Pd/C, Quinoline

  • Option 3)

    Zn/ HCl

  • Option 4)

    Hg2+/H+, H2O

Option 1)Na/liquid NH3Option 2)H2, Pd/C, QuinolineOption 3)Zn/ HClOption 4)Hg2+/H+, H2O
Medical
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In the reaction 

 H-C\equiv CH \frac{(1)N_{a}NH_{2}/liq.NH_{3}}{(2)CH_{3}CH_{2}Br}X\\ \frac{\left ( 2 \right )N_{a}NH_{2}/liq.NH_{3}}{\left ( 2 \right )CH_{3}CH_{2}Br}Y 

X and Y are

  • Option 1)

    X=1-Butyne; Y=3-Hexyne

  • Option 2)

    X=2-Butyne; Y=3-Hexyne

  • Option 3)

    X=2-Butyne; Y=3-Hexyne

  • Option 4)

    X=1-Butyne; Y=2-Hexyne

 
As we learnt in  Birch Reduction - Alkynes on reduction with sodium in liquid NH3 form trans alkene. - wherein   X=1-Butyne,      Y= 3-Hexyne Option 1) X=1-Butyne; Y=3-Hexyne This option is correct Option 2) X=2-Butyne; Y=3-Hexyne This option is incorrect Option 3) X=2-Butyne; Y=3-Hexyne This option is incorrect Option 4) X=1-Butyne; Y=2-Hexyne This option is incorrect
Medical
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Which of the following compounds shall not produce propene by reaction with HBr followed by elimination or direct only elimination reaction?

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 
As we learnt in Addition of Hydrogen Halide on alkene - hydrogen halides add up to alkenes to form alkyl halides. The order of reactivity of the hydrogen halides is HI>HBr>HCl - wherein   (1)     (2)     (3)     (4)         Option 1) Incorrect Option 2) Incorrect Option 3) Correct Option 4) Incorrect
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