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  • A car starts from rest and moves along the x-axis with constant acceleration 5 ms^–2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?

A car starts from rest and moves along the x-axis with constant acceleration 5ms^{-2} for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?

 

Answers (1)

For the first eight seconds, the car is moving with constant acceleration with zero initial velocity.

Hence, we can use equations of motion to find out the distance and final velocity after that time interval of eight seconds.

s =ut +\frac{1}{2}at^{2}

v = u + at

where u=0 , a =5 , t=8

By putting values

s = 160 m

v = 40 m/s

Now for the next four seconds, the car will move at a constant speed of 40 m/s. Hence, in this time interval, it will travel 160 m.

Therefore, the total distance travelled will be 320 m.

Posted by

infoexpert21

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