A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment
30o
Solution:
Given that a chord of a circle is equal to its radius
Let the chord be AB as shown in the figure.
AB = Radius of Circle.
Now, AB = OA = OB
In OAB,
AB = OA = OB = radius
Hence it is an equilateral triangle. So all angles are 60o
OAB =ABO = BOA = 60o
Let point D be a point on the major arc.
Considering the arc AB, we know that angle subtended at the centre by an arc is twice the angle subtended by it at any part of the circle
So,