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  • A compound (A) of boron reacts with NMe_3 to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A, B and C. Give the reactions involved

A compound (A) of boron reacts with NMe3 to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A, B and C. Give the reactions involved

Answers (1)

Compound A reacts with Boron and gives [B], and thus A is a Lewis acid as it accepts electrons. [B] reacts with [C] and liberates hydrogen and thus [A] isB_{2}H_{6}.  B is thus 2BH_{3}NMe_{3} and C is boric acid.

A = B_{2}H_{6} (DIBORANE)

B = 2BH_{3}NMe_{3} (ADDUCT)

C = 2B_{3}N_{3}H_{6} (INORGANIC BORAZINE)

B_{2}H_{6} + 2NMe_{3}\rightarrow 2BH_{3}NMe_{3}

3 B_{2}H_{6} + 6NH_{3} \rightarrow 3[BH_{3}(NH_{3})_{2}]+[BH_{4}]^{+} \rightarrow 2B_{3}N_{3}H_{6} + 12H_{2}

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