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A compound X, of boron reacts with $NH_{3}$ on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating $BF_{3}$ with Lithium aluminium hydride. The compounds X and Y are represented by the formulas.
$(i) B_{2}H_{6} , B_{3}N_{3}H_{6}$
$(ii) B_{2}O_{3}, B_{3} N_{3} H_{6}$
$(iii) BF_{3}, B_{3}N_{3} H_{6}$
$(iv) B_{3}N_{3}H_{6} , B_{2}H_{6}$

Answers (1)

The answer is the option $(i) B_{2}H_{6} , B_{3}N_{3}H_{6}$

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