A copper and a steel wire of the same diameter are connected end to end. A deforming force F is applied to this composite wire which causes a total elongation of 1 cm. The two wires will have

a) the same stress

b) different stress

c) the same strain

d) different strain

Answers (1)

The answer is the option (a) and (d).

As we know stress =

\frac{F}{A}

The areas of cross-sections of both wires are the same, and the force with which they get stretched is also the same. Hence the total stress for both is the same. Hence option a.

Strain = Stress/Y

As stresses are same on both,

Strain \propto \frac{1}{Y} (steel) and Strain \propto \frac{1}{Y} (Al)

Strain (steel)/ Strain (Al) = Y (Al) / Y(steel)

Now, Y(Al) < Y (Steel). Hence, strain(steel) < Strain (Al)

Hence, option d is correct.

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