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Get Answers to all your Questions
The Young’s modulus for steel is more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?
Answers (1)
Y = stress/strain and Y stress
Y (steel)/ Y(rubber) = Stress(steel)/Stress(rubber)
We know that Y steel > Y rubber
Y steel/Y rubber > 1
Hence, stress (steel)/stress (rubber) > 1
So, stress (steel) > stress (rubber)
View full answer
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