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A cubic vessel (with face horizontal + vertical) contains an ideal gas at NTP. The vessel is being carried by a rocket which is moving at a speed of 500 ms^{-1} in the vertical direction. The pressure of the gas inside the vessel as observed by us on the ground
(a) remains the same because 500 ms^{-1} is very much smaller than vrms of the gas.
(b) remains the same because the motion of the vessel as a whole does not affect the relative motion of the gas molecules and the walls.
(c) will increase by a factor equal to\frac{\left ( v^{2}rms +\left ( 500 \right )^{2} \right )}{v^{2}rms} where vrms was the original mean square velocity of the gas.
(d) will be different on the top wall and bottom wall of the vessel.

Answers (1)

The answer is the option (b)

In the rocket, the relative velocity of molecules does not change with respect to walls of a container as the mass of a molecule when compared to that of the whole system is negligible. So, the whole gas system moves as a single unit. The rocket moves at a constant speed which makes the acceleration zero, and hence the pressure remains the same as observed by us inside the gas vessel.

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