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A gas mixture consists of molecules of A, B and C with massesm_{A} > m_{B} > m_{c}. Rank the three types of molecules in decreasing order of (a) average KE, (b) RMS speeds.

Answers (1)

Vav =\sqrt{\frac{8 K_bT}{\pi m}} = \sqrt{\frac{8RT}{\pi m}} = \sqrt{\frac{8PV}{\pi m}}

as the temperature and pressure are equal,

Vav\propto \frac{1}{\sqrt{m}}

hence, Vc > Vb > Va

now KE \propto V^2 and KE \propto m

hence KE in decreasing order will be,

KE c > KE b > KE a

b)

now, V_{rms} =\sqrt{\frac{3K_bT}{m}}

since it is given that, m(a) > m(b) > m(c)

V_ {rms} (c) > V_{ rms} (b) > V_{ rms} (a)

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