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  • A helicopter of mass 2000 kg rises with a vertical acceleration of 15 m/s^2. The total mass of the crew and passengers is 500 kg. Give the magnitude and direction of the a) force on the floor of the helicopter by the crew and passengers

A helicopter of mass 2000 kg rises with a vertical acceleration of 15 m/s2. The total mass of the crew and passengers is 500 kg. Give the magnitude and direction of the

a) force on the floor of the helicopter by the crew and passengers

b) action of the rotor of the helicopter on the surrounding air

c) force on the helicopter due to the surrounding air

Answers (1)

Let, M be the mass of the helicopter, M = 2000 kg

m be the mass of the crew and passengers, m = 500 kg

& a be the acceleration of the helicopter with the passengers and crew, a = 15 ms-2

(a) Force on the floor of the helicopter = apparent weight

                                                                = m (g + a)

                                                                = 500 (10 + 15)

Thus F1= 500 (25)

           = 12588N downward

(b)The action rotor of the helicopter which surrounds the air = Reaction force (by Newton’s 3rd law),

Due to this, the helicopter rises up along with the crew and passengers with acceleration viz.,

15 ms-1 = (M + m) (g + a).

Thus, the action of the rotor = (2000 + 500) (g + a).

Thus, F2 = 2500 (10 + 15)

                = 2500 (25)

                = 62500 N downward.

(c) Let F3 be the force acting on the helicopter by the reaction force of the surrounding air.

According to Newton’s 3rd law

F3 = -Action force

    = -62500 N downward or F3 = + 62500 N upward.

Posted by

infoexpert24

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