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Q5.13. A man of mass 70 kg stands on a weighing scale in a lift which is moving

(a) upwards with a uniform speed of 10 m s-1 

What would be the readings on the scale in each case?

Answers (1)

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Since lift is moving with a constant speed or in this case constant velocity so the acceleration provided to man by lift is zero.

The net force on the man will be zero. So a = 0.

Using Newton's law of motion, we can write :

                                                               R\ -\ mg\ =\ ma

or                                                            R\ -\ mg\ =\ 0

Thus                                                       R\ =\ mg

                                                                      =\ 70\times10\ =\ 700\ N

So, reading on weighing scale will be :

                                                                     =\ \frac{R}{g}\ =\ \frac{700}{10}\ =\ 70\ Kg

Posted by

Devendra Khairwa

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