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  • A tuning fork A, marked 512 Hz, produces 5 beats per second, where sounded with another unmarked tuning fork B. If B is loaded with wax the number of beats is again 5 per second. What is the frequency of the tuning fork B when not loaded?

A tuning fork A, marked 512 Hz, produces 5 beats per second, where sounded with another unmarked tuning fork B. If B is loaded with wax the number of beats is again 5 per second. What is the frequency of the tuning fork B when not loaded?

Answers (1)

v_{A}=512

v_{o}=v_{A}-v_{B}

On loading frequencies of B decreases 

 v_{1}=5

v_{B}=v_{A}\pm 5

v_{B}=512\pm 5=507 or 517

Therefore, on loading the frequency of B decreases to 507

Frequency of tuning fork, when unloaded, is 517 Hz.

(When frequency decreases by 10 Hz the number of beats will be same as 512-507=5)

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infoexpert24

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