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A violet compound of manganese (A) decomposes on heating to liberate oxygen and compounds (B) and (C) of manganese are formed. Compound (C) reacts with KOH in the presence of potassium nitrate to give compound (B). On heating compound (C) with cone. H_{2}SO_{4} and NaCl, chlorine gas is liberated and a compound (D) of manganese along with other products is formed. Identify compounds A to D and also explain the reactions involved.

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The compounds A,B, C and D are given as :

A=KMnO_{4} \; \; \; \; \; \; \; B=K_{2}MnO_{4}\; \; \; \; \; \; \; C=MnO_{2}\; \; \; \; \; \; D=MnCl_{2}

The reactions are as KMnO_{4} (A)\overset{\Delta }{\rightarrow}K_{2}MnO_{4} (B)+MnO_{2}(C)+O_{2}

MnO_{2}+KOH+O_{2}\rightarrow 2K_{2}MnO_{4} +2H_{2}O

MnO_{2}+4NaCl +4H_{2}SO_{4}\rightarrow MnCl_{2}(D)+2NaHSO_{4}+2H_{2}O+Cl_{2}

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