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  • When a chromite ore (A) is fused with sodium carbonate in free excess of air and the product is dissolved in water, a yellow solution of compound (B) is obtained.

When a chromite ore (A) is fused with sodium carbonate in free excess of air and the product is dissolved in water, a yellow solution of compound (B) is obtained. After treatment of this yellow solution with sulphuric acid, compound (C) can be crystallized from the solution. When compound (C) is treated with KCl, orange crystals of compound (D) crystallise out. Identify A to D and also explain the reactions.

Answers (1)

The compounds A, B, C and D are given as under:

\text {A=FeCr}_{2}\text {O}_{4}\; \; \; \; \; \text {B=Na}_{2}\text {CrO}_{4}\; \; \; \; \; \text {C=Na}_{2}\text {Cr}_{2}\text {O}_{7}.\text {2H}_{2}\text {O} \; \; \; \; \; \; \text {D=K}_{2}\text {Cr}_{2}\text {O}_{7}

Following are the reactions :

4FeCr_{2}O_{4}(A)+8NaCO_{3}+7O_{2}\rightarrow 8Na_{2}CrO_{4} (B)+2Fe_{2}O_{3}+8CO_{2}

2NaCrO_{4}+2H^{+}\rightarrow Na_{2}Cr_{2}O_{7} +2Na^{+}+H_{2}O

Na_{2}Cr_{2}O_{7} (C)+2KCl\rightarrow K_{2}Cr_{2}O_{7}+2NaCl

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