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1.24 Aluminium crystallises in a cubic close-packed structure. Its metallic radius is 125 pm.
(i) What is the length of the side of the unit cell?

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For cubic close-packed structure,

we have $a=2\sqrt{2} . r$

Given : $r=125 pm$

$a =2\times 1.414\times 125$

$a=354 pm$

Posted by

seema garhwal

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