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An amplitude modulated wave is as shown in the figure. Calculate

(i) the percentage modulation

(ii) peak carrier voltage and

(iii) peak value of information voltage

Answers (1)

As shown in the figure,

Maximum voltage, Vmax = 100/2 = 50 V

Minimum voltage, Vmin = 20/2 = 10 V

i) Percentage modulation = (Vmax - Vmin)/(Vmax + Vmin) \times 100

After substituting the values of Vmax and Vmin, the percentage modulation = 66.67%

ii) the formula of peak carrier voltage is Vc =( Vmax + Vmin)/2

Thus,Vc = 30 V

iii) Peak value of information voltage  = Vm = uVc = 20V

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