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2.44    An ion with mass number 56 contains 3 units of positive charge and 30.4% more neutrons than electrons. Assign the symbol to this ion.

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Given an ion has mass number 56 and possesses three units of negative charge.

Let the number of electrons be 'e' then,

the number of neutrons will be: e+\frac{30.4e}{100} = 1.304e

The number of electrons in the neutral atom = e+3 (ion possesses three units of positive charge).

Therefore, the number of protons will be = e+3.

Mass number = number of protons + number of neutrons

therefore, 

1.304e +e +3 =56

\Rightarrow 2.304e =53

\Rightarrow e =23

Therefore, the number of protons is equal to the atomic number.

\Rightarrow e+3 = 23+3 =26

Hence, the symbol for an ion will be:

_{26}^{56}\textrm{Fe}^{3+}

Posted by

Divya Prakash Singh

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