Q. 2  An urn contains 5 red and 2 black balls. Two balls are randomly drawn. Let X represent the number of black balls. What are the possible values of X? Is X a random variable ?

Answers (1)

B = black balls

R = red balls

The two balls can be selected as BR,BB,RB,RR.

X = number of black balls.

\therefore     X(BB)=2

         X(RB)=1

         X(BR)=1

          X(RR)=0

Hence, possible values of X can be 0, 1 and 2.

Yes, X is a random variable.

 

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