Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Assuming complete dissociation, calculate the pH of the following solutions: (b) 0.005 M NaOH

Q 7.48     Assuming complete dissociation, calculate the pH of the following solutions: 

     (b)      0.005 M NaOH 

Answers (1)

$\begin{aligned} & \mathrm{NaOH}_{(a q)} \longleftrightarrow \mathrm{Na}_{(a q)}^{+}+\mathrm{HO}_{(a q)}^{-} \\ & {\left[\mathrm{HO}^{-}\right]=[\mathrm{NaOH}]} \\ & \Rightarrow\left[\mathrm{HO}^{-}\right]=.005 \\ & \mathrm{pOH}=-\log \left[\mathrm{HO}^{-}\right]=-\log (.005) \\ & \mathrm{pOH}=2.30 \\ & \therefore \mathrm{pH}=14-2.30 \\ & \quad=11.70\end{aligned}$

Posted by

Satyajeet Kumar

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE 12th Result 2026: Board refutes OSM glitch claims, says Class 12 results likely in third week of May
anam-khan

CBSE 12th Result 2026 LIVE: Class 12 results soon at cbse.gov.in, direct link, digilocker, pass percentage
anam-khan

CBSE 12th Result 2026 Date LIVE: Class 12 marksheet on cbse.gov.in, DigiLocker soon; OSM system, passing marks

Latest Question