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  • Calculate the volume occupied by 8.8 g of CO_2 at 31.1°C and 1 bar pressure.

5.17     Calculate the volume occupied by 8.8 g of CO_{2} at 31.1°C and 1 bar pressure.  R = 0.083 \: bar \: L\: K^{-1} mol^{-1}.

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Given the mass of carbon dioxide is 8.8grams at 31.1^{\circ}C and at 1 bar pressure.

So, the number of moles of 

CO_{2} (n) = \frac{Mass\ of\ CO_{2}}{Molar\ Mass}

= \frac{8.8g}{44g\ mol^{-1}} = 0.2\ mol

Now, the pressure of CO_{2} (P) = 1\ bar

Given R = 0.083 \: bar \: L\: K^{-1} mol^{-1}

also, the Temperature (T) = 273+31.1 = 304.1K

The Ideal gas equation; PV=nRT

V=\frac{nRT}{P} = \frac{0.2\times 0.083\times304.1}{1\ bar} = 5.048L

So volume occupied by 8.8 g of carbon dioxide is 5.048L

Posted by

Divya Prakash Singh

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