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Q. 17.     Calculate the work required to be done to stop a car of   1500\; kg   moving at a velocity of  60\; km/h ?

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Firstly convert the velocity in SI unit.

                                           v\ =\ 60\times \frac{5}{18}\ =\ \frac{50}{3}\ m/s

Thus the work done to stop the car is equal to the kinetic energy of the car.

                                                  W\ =\ \frac{1}{2}mv^2\ =\ \frac{1}{2}\times 1500\times \left ( \frac{50}{3} \right )^2 

or                                                                              =\ 208333.33\ J\ or\ 208.33\ KJ

Posted by

Sanket Gandhi

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