Q

# Carry out the following divisions -36 y^3 / 9 y^2

q1) Carry out the following divisions

ii)

$-36 y^3 \div 9 y^2$

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We have,
$-36$$y^{3}$ $= -1 \times 2 \times 2 \times 3 \times 3 \times y \times y \times y$
$9$$y^{2 }$  $= 3 \times 3 \times y \times y$
Therefore,
$\frac{-36y^{3}}{9y^{2}} = \frac {-1 \times 2 \times 2 \times 3 \times 3 \times y \times y \times y}{3 \times 3 \times y \times y} = -4y$

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