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  • Consider a two slit interference arrangements (Fig. 10.4) such that the distance of the screen from the slits is half the distance between the slits.

Consider a two-slit interference arrangement (Fig. 10.4) such that the distance of the screen from the slits is half the distance between the slits. Obtain the value of D in terms of such that the first minima on the screen fall at a distance D from the centre O.



 

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S_1P = \sqrt{D^2} + (D - x)^2\\\\S_2P = \sqrt{D^2} +(D- x)^2 \\\ T_2P = D + x \\\ T_2P = D - x \\ \\ \left [ D^{2} +(D+x)^{2} \right ]^{1/2}- \left [ D^{2} +(D-x)^{2} \right ]^{-1/2} =\frac{\lambda}{2} \\\\D = 0.404 \lambda

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Gurleen Kaur

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