# 5  Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint  $100 m^{2}$ of area is painted. How many cans of paint will she need to paint the room?

Total area painted by Daniel :

$= 2(15\times10+10\times7+7\times15) - 15\times10$                                   ($\because$  Bottom surface is excluded.)

So,  Area

$= 650 - 150\ m^2 = 500\ m^2$

No. of cans of paint required

$=\frac{ 500\ m^2}{100\ m^2} = 5$

Thus 5 cans of paint are required.

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