Q1 Find the common factors of the given terms 

(vi)16 x ^ 3 , -4 x ^ 2 , 32 x

Answers (1)

We have, 
             16x^3 = 2 \times 2 \times {\color{Red} 2 \times 2 \times x} \times x \times x
             4x^2 = {\color{Red} 2 \times 2 \times x} \times x
              32x = 2 \times 2 \times 2 \times{\color{Red} 2 \times 2 \times x}
Therefore, the common factors is 

2 \times 2 \times x = 4x

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