Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the domain of the function f (x) = x ^2 + 2x +1 / x^2 - 8x +12

3. Find the domain of the function f (x) = \frac{x^2 + 2 x +1}{x^2 - 8x + 12 }

Answers (1)

best_answer

Given function is 
f (x) = \frac{x^2 + 2 x +1}{x^2 - 8x + 12 }
Now, we will simplify it into
f (x) = \frac{x^2 + 2 x +1}{x^2 - 8x + 12 }
           = \frac{x^2+2x+1}{x^2-6x-2x+12}
           = \frac{x^2+2x+1}{x(x-6)-2(x-6)}
           = \frac{x^2+2x+1}{(x-2)(x-6)}
Now, we can clearly see that  x \neq 2 , 6
Therefore, the Domain of f(x)  is (R-\left \{ 2,6 \right \})
 

Posted by

Gautam harsolia

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE practical exams 2026 will be cancelled over non-compliance with guidelines, says board

Latest Question