Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the sum to indicated number of terms in each of the geometric progressions in 0.15, 0.015, 0.0015, ... 20 terms.

7.  Find the sum to indicated number of terms in each of the geometric progressions in  0.15, 0.015, 0.0015, ... 20 terms.

Answers (1)

best_answer

geometric progressions is  0.15, 0.015, 0.0015, ... .....

a=0.15 , r = 0.1 , n=20

S_n=\frac{a(1-r^n)}{1-r}

S_2_0=\frac{0.15(1-(0.1)^{20})}{1-0.1}

S_2_0=\frac{0.15(1-(0.1)^{20})}{0.9}

S_2_0=\frac{0.15}{0.9}(1-(0.1)^{20})

S_2_0=\frac{15}{90}(1-(0.1)^{20})

S_2_0=\frac{1}{6}(1-0.1^{20})

Posted by

seema garhwal

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

‘Stop defending your so-called flawless OSM’: Class 12 students slam CBSE over blurred answer sheets
anam-khan

'CBSE failed us, again!': Board faces backlash as Class 12 re-evaluation portal remains inaccessible
anam-khan

CBSE Class 12 re-evaluation portal faces technical glitch, services to resume by 2 pm

Latest Question