Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • For some constants a and b, find the derivative of x - a/x-b

7.(iii)   For some constants a and b, find the derivative of \frac{x - a }{x -b }

Answers (1)

best_answer

Given,

f(x)=\frac{x - a }{x -b }

Now As we know the quotient rule of derivative,

\frac{d(\frac{y_1}{y_2})}{dx}=\frac{y_2\frac{dy_1}{dx}-y_1\frac{dy_2}{dx}}{y_2^2}

So applying this rule, we get

\frac{d(\frac{x-a}{x-b})}{dx}=\frac{(x-b)\frac{d(x-a)}{dx}-(x-a)\frac{d(x-b)}{dx}}{(x-b)^2}

\frac{d(\frac{x-a}{x-b})}{dx}=\frac{(x-b)-(x-a)}{(x-b)^2}

\frac{d(\frac{x-a}{x-b})}{dx}=\frac{a-b}{(x-b)^2}

Hence 

f'(x)=\frac{a-b}{(x-b)^2}

Posted by

Pankaj Sanodiya

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Admit Card 2026 (OUT) LIVE: Class 10 and 12 theory exam hall ticket at parikshasangam.cbse.gov.in
anam-khan

CBSE Admit Card 2026 LIVE: How to download CBSE Class 10th, 12th hall ticket when out; exam dates, guidelines
anam-khan

CBSE 2026 Admit Card LIVE: CBSE Class 10, 12 hall ticket soon at cbse.gov.in; direct link, datesheet, updates

Latest Question