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Q.1. Given that $E$ and $F$ are events such that $P(E)=0.6,P(F)=0.3$ and $p(E\cap F)=0.2,$ find $P(E\mid F)$ and $P(F\mid E)$

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It is given that $P(E)=0.6,P(F)=0.3$ and $p(E\cap F)=0.2,$

$P ( E | F ) = \frac{p(E\cap F)}{P(F)}= \frac{0.2}{0.3}= \frac{2}{3}$

$P ( F | E ) = \frac{p(E\cap F)}{P(E)}= \frac{0.2}{0.6}= \frac{1}{3}$

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seema garhwal

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