2.35    Henry’s law constant for the molality of methane in benzene at 298\; K is 4.27\times10^{5} mm\ Hg. Calculate the solubility of methane in benzene at  298\; K under 760\; mm\; Hg.

Answers (1)

We know that :            P = k\times C

We are given value of P and k, so C can be found.

                                     C = \frac{760}{4.27\times10^5} = 178\times 10^{-5}

Hence solubility of methane in benzene is 178\times 10^{-5}.

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