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3.12     How much charge is required for the following reductions:

             (ii)  1\ mol \ of\ Cu^{2+}\ to\ Cu?

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The equation can be written as:-

                                                          Cu^{2+}\ +\ 2e^-\ =\ Cu

Thus charge required is  =\ 2F

                                        = 2(96500) = 193000\ C   

Posted by

Devendra Khairwa

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